Working with ajax examples.

Mark
I am not an expert at AJAX and I am trying to get this code to work. This is the example code.
html>
<?php
/*
* This file is ready to run as standalone example. However, please do:
* 1. Add tags <html><head><body> to make a complete page
* 2. Change relative path in $KoolControlFolder variable to correctly point to KoolControls folder
*/
$KoolControlsFolder = "/web/KoolPHPSuite/KoolControls/";//Relative path to "KoolPHPSuite/KoolControls" folder
require $KoolControlsFolder."KoolAjax/koolajax.php";
$koolajax->scriptFolder = $KoolControlsFolder."KoolAjax";
function calculate($x,$y)
{
return $x+$y;
}
//Enable calculate function to be called at client-side
$koolajax->enableFunction("calculate");
?>
<form id="form1" method="post">
<?php
echo $koolajax->Render();
?>
<style type="text/css">
#loading
{
position:relative;
left:-22px;
top:3px;
visibility:hidden;
}
</style>
<div>
<input id="txtX" type="textbox" value="2" /> +
<input id="txtY" type="textbox" value="3" />
<input id="btnCal" type="button" value="Calculate" onclick="btnCal_Click()" />
<input id="txtZ" type="textbox" />
<img id="loading" src="Images/loading.gif" alt="Loading..." />
</div>
<script type="text/javascript">
function btnCal_Click()
{
x = document.getElementById("txtX").value;
y = document.getElementById("txtY").value;
koolajax.callback(calculate(x,y),onDone);
document.getElementById("loading").style.visibility ="visible";
}
function onDone(s)
{
document.getElementById("txtZ").value = s;
document.getElementById("loading").style.visibility ="hidden";
}
</script>
</form>
</html>

Any thoughts?
Posted Jul 1 Kool
Anthony Amolochitis
It seems KoolAjax didn't render.
Check to make sure your require path is set correctly.
Posted Jul 4 Kool
Mark
OK will do, thanks for your help.
Posted Jul 4 Kool